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4.905t^2-8.275t+0.65=0
a = 4.905; b = -8.275; c = +0.65;
Δ = b2-4ac
Δ = -8.2752-4·4.905·0.65
Δ = 55.722625
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-8.275)-\sqrt{55.722625}}{2*4.905}=\frac{8.275-\sqrt{55.722625}}{9.81} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-8.275)+\sqrt{55.722625}}{2*4.905}=\frac{8.275+\sqrt{55.722625}}{9.81} $
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